@apple vs @asos TikTok

Side-by-side TikTok statistics, updated 4 days ago.

@apple vs @asos: stats compared

Metric@apple@asos
Followers 9.3MWinner 2.3M
Total views 266.9M 451.5MWinner
Avg views / post 8.9MWinner 617.6K
Engagement rate 6%Winner 0.9%
Likes 13.1MWinner 3.8M
Comments 126.3KWinner 15.5K
Shares 2MWinner 123.8K
Tracked posts 30 731Winner
Est. sponsored post $139.4KWinner $5.1K

Winner badges mark the higher value per metric. Sponsored-post figures are modeled estimates, not quotes.

Verdict

@apple leads @asos in 7 of the 9 compared TikTok metrics (vs 2). @apple has the larger audience, with 7M more followers. @apple's audience is the more engaged one at 6% — on short-form platforms, engagement is the better predictor of sponsorship performance than raw follower count.

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Frequently asked questions

Who has more followers, @apple or @asos?

@apple has more followers: 9,291,400 vs @asos's 2,254,741 on TikTok as of July 2026.

Who has the higher engagement rate, @apple or @asos?

@apple has the higher engagement rate at 6%, compared with 0.9% for @asos. Engagement rate is total interactions divided by total views across tracked posts.

Who charges more for a sponsored post, @apple or @asos?

Based on followers and engagement, @apple likely commands the higher rate: @apple is estimated at $111.5K–$167.2K per sponsored TikTok post, @asos at $4.1K–$6.1K. Estimates, not quotes.

How is this TikTok comparison calculated?

Buzzlytics tracks both accounts' public TikTok data. Each metric compares the latest snapshot of each account; the winner badge marks the higher value. Sponsored-post figures are modeled estimates from followers and engagement rate.

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Data source & methodology

Buzzlytics tracks publicly available TikTok profile data. Each column reflects the latest tracked snapshot of that account (@apple: 25 days ago; @asos: 4 days ago). Engagement rate is total interactions divided by total views. Nothing here is provided by or affiliated with TikTok. Profile owners can request removal via support@buzzlytics.io.